The domain of 2√(x − 6)

For REAL numbers ,   anything that makes the sqrt 0 or greater   i.e.   x >= 6

\(2\sqrt{x-6}\)

In order for this expression to have a domain, the expression needs to have an \(x\) and a \(y\) and be changed to an equaton

\(y=2\sqrt{x-6}\)

In this case, in order to find the domain, find what the restrictions of \(x\) are by setting \(x-6≥0\) and solve for x.  

\(x+6≥0\)

\(x≥-6\)

Domain: \(x≥-6\)

If you set \(x-6<0,\) you wlll get a negetive number which you cannot take the square root of a negetive number without using imaginary numbers.