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The equation \(y = -16t^2 + 80t\) describes the height (in feet) of a projectile launched from the ground at 80 feet per second. At what t will the projectile reach 36 feet in height for the first time? Express your answer as a decimal rounded to the nearest tenth.

 Dec 2, 2020
 #1
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  36    =  -16t^2 + 80 t

-16t^2 +80t -36 = 0        use quadratic formula to find values of  t

a = -16    b = 80   c = -36

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)                         the smaller 't' value will be the FIRST time it is at 36 ft 

                                                               the other 't' value will be when it is on the way down

 Dec 2, 2020
 #2
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 Express your answer as a decimal rounded to the nearest tenth.

Guest Dec 2, 2020
 #3
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CPHill help

 Dec 2, 2020
 #4
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You obviously don't want 'help' ....you want someone to spoonfeed you the answers.....don't play on cphill's willingness to help !!!

Guest Dec 2, 2020

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