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The equation of a parabola is (y−1)2=16(x+3) .

 

What is the equation of the directrix of the parabola?

 

Enter your answer in the box.

lysxsa  May 23, 2018
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\((y-1)^2 = 16(x+3)\\ 4(4)(x-(-3)) = (y-1)^2\\ p = 4\)

The focus of the parabola is 4 units on the right of the vertex.

Therefore the directrix of parabola is x = -3-4, i.e., x = -7.

MaxWong  May 24, 2018

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