The equation of the line that goes through the point (3,3) and is parallel to the line going through the points \(( -5 ,1 ) and ( 1 ,1 )\) can be written in the form \( y = mx+b \) where m is: and b is:

Find the slope of the line going through (-5,1) and (1,1) using the slope formula: m=(y_{2}-y_{1})/(x_{2}-x_{1)} m=(1-1)/(1--5) m=0/6

m=0

Parallel lines have the same slope, so the slope of the parallel line is 0. Plug in (3,3) to y=mx+b as (x,y) 3=0(3)+b b=3 line is y=3