+0  
 
0
130
1
avatar+81 

The equation of the line that goes through the point (3,3)  and is parallel to the line going through the points \(( -5 ,1 ) and ( 1 ,1 )\) can be written in the form \( y = mx+b \) where 
m is:  
and b is:  

Sloan  Jun 13, 2018
 #1
avatar+84 
0

Find the slope of the line going through (-5,1) and (1,1) using the slope formula:
m=(y2-y1)/(x2-x1)
m=(1-1)/(1--5)
m=0/6

m=0

 

Parallel lines have the same slope, so the slope of the parallel line is 0.
Plug in (3,3) to y=mx+b as (x,y)
3=0(3)+b
b=3

line is y=3


 

ChowMein  Jun 13, 2018

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