The equation of the line that goes through the point (3,3) and is parallel to the line going through the points (−5,1)and(1,1) can be written in the form y=mx+b where m is: and b is:
Find the slope of the line going through (-5,1) and (1,1) using the slope formula: m=(y2-y1)/(x2-x1) m=(1-1)/(1--5) m=0/6
m=0
Parallel lines have the same slope, so the slope of the parallel line is 0. Plug in (3,3) to y=mx+b as (x,y) 3=0(3)+b b=3 line is y=3
+81 
