The graph of the equation y=22.2-42.2*0.6^x has a horizontal asymptote. What would be the equation of this asymptote?

Guest Feb 20, 2020

#1**+1 **

y = 22.2 - 42.2* 0.6^x

Note that as x gets larger and larger, the term 42.2*0.6^x virtually evaluates to 0

So.....the horizontal asymptote = y = 22.2 - (0) ⇒ y = 22.2

See the graph of this here : https://www.desmos.com/calculator/luywbdkzfx

CPhill Feb 20, 2020

#2**+1 **

Thank you! In my assignment they also ask me what the horizontal assympote ""means/shows"". The assignment is about counting the owls in a city, and x originally was t for time. So if t gets larger the quantity of owls practically turns to zero then?

Guest Feb 20, 2020