The graph of the equation y =ax^2 + bx + c, where a, b, and c are constants, is a parabola with axis of symmetry x = -3. Find b/a.

Question

0

1708

1

The graph of the equation \(y =ax^2 + bx + c\) , where a, b, and c are constants, is a parabola with axis of symmetry x = -3. Find \(b/a\).

Guest Aug 9, 2016

CPhill · Answer 1 · 2016-08-09T06:08:07

The graph of the equation ax^2 + bx + c , where a, b, and c are constants, is a parabola with axis of symmetry x = -3. Find b/a

The x coordinate of the vertex, - 3, is given by -b/[2a]

So ... -b/[2a] = -3 → b = 6a → b/a = 6

.