The graph of the equation $y =ax^2 + bx + c$ where a, b, and c are constants, is a parabola with axis of symmetry where x = -3. Find b/a
One important thing to note is that the equation for the line of symmetry for a quadratic is x= -b/(2a).
So, -b/(2)a = -3
b/(2a)=3
b/a=6.
One important thing to note is that the equation for the line of symmetry for a quadratic is x= -b/(2a).
So, -b/(2)a = -3
b/(2a)=3
b/a=6.