+0  
 
0
649
1
avatar

The graph of the equation $y =ax^2 + bx + c$ where a, b, and c are constants, is a parabola with axis of symmetry where x = -3. Find b/a

 Mar 14, 2019

Best Answer 

 #1
avatar+937 
+1

One important thing to note is that the equation for the line of symmetry for a quadratic is x= -b/(2a).

 

So, -b/(2)a = -3

b/(2a)=3

b/a=6.

 Mar 15, 2019
 #1
avatar+937 
+1
Best Answer

One important thing to note is that the equation for the line of symmetry for a quadratic is x= -b/(2a).

 

So, -b/(2)a = -3

b/(2a)=3

b/a=6.

dgfgrafgdfge111 Mar 15, 2019

4 Online Users

avatar
avatar