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The graph of the equation $y =ax^2 + bx + c$ where a, b, and c are constants, is a parabola with axis of symmetry where x = -3. Find b/a

 Mar 14, 2019

Best Answer 

 #1
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One important thing to note is that the equation for the line of symmetry for a quadratic is x= -b/(2a).

 

So, -b/(2)a = -3

b/(2a)=3

b/a=6.

 Mar 15, 2019
 #1
avatar+429 
+1
Best Answer

One important thing to note is that the equation for the line of symmetry for a quadratic is x= -b/(2a).

 

So, -b/(2)a = -3

b/(2a)=3

b/a=6.

dgfgrafgdfge111 Mar 15, 2019

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