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The graph of the quadratic y = ax^2 + bx + c has the following properties: (1) The maximum value of y = ax^2 + bx + c is 5, which occurs at x = -3. (2) The graph passes through the point (0,-11). If the graph passes through the point (4,m), then what is the value of m?

 Nov 1, 2020
 #1
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-b/2a = -3      and  a(-3^2) + b(-3)+c=5    and    a(0) + b*0 +c = -11     so c = -11

b/2a = 3                     9a -3b =16

a =b/6                        9 (b/6) -3b=16      b = -10.667      a =1.778

                                     

 

 

.......   m = -82.111

graph:

https://www.desmos.com/calculator/0b6334urym

 Nov 1, 2020
 #2
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*** edit ***     a= - 1.778

Guest Nov 1, 2020

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