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The greatest common divisor of two integers is x + 5 and their least common multiple is x(x + 5) , where x is a positive integer. If one of the integers is 60, what is the smallest possible value of the other one?

 Nov 1, 2020
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x=0;p=0; y=0;z=0;n=gcd(y, 60);m=lcm(y, 60);if(n==x+5 and m==x*(x+5), goto loop, goto next);loop:p=p+1;printp," =",x,y;next:x++;if(x<200, goto4,0);x=0;y++;if(y<200, goto4, 0)

 

x = 15.  Your two integers are: 60  and the smallest possible value of the 2nd integer = 100.

GCD[60, 100] =[x + 5] =[15 + 5] = 20

LCM[60,100] =x[x + 5] =15*[15 + 5] =15 * 20 =300

 Nov 1, 2020

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