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 The height h (in feet) of a certain rocket t seconds after it leaves the ground is modeled by h(t)= -16t^2 + 48t + 15. Find the

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The height h (in feet) of a certain rocket t seconds after it leaves the ground is modeled by h(t)= -16t^2 + 48t + 15. Find the maximum height reached by the rocket.

I have been puzzled by this for about 45 mins. Anyone who helps me, I will be very 10000% greatful!!

Thank you!

 :)

 Dec 17, 2015

Best Answer 

 #2
avatar+129852 
+10

h(t)= -16t^2 + 48t + 15

 

The maximum height will be reached after   -b/2a secods =  -48/2(-16)   = 48/32 = 1.5 seconds

 

Then.....the max ht =    -16(1.5)^2 + 48(1.5) + 15  =  -16(2.25) + 72 + 15 =  51 ft

 

Here's the graph........https://www.desmos.com/calculator/poqqwhpqok

 

 

cool cool cool

 Dec 17, 2015

3+0 Answers

 #1
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0

Huhhhhhh? I get why you've been confused lol😀😜😀😜😀😜

 

       -Victoria 

 Dec 17, 2015
 #2
avatar+129852 
+10
Best Answer

h(t)= -16t^2 + 48t + 15

 

The maximum height will be reached after   -b/2a secods =  -48/2(-16)   = 48/32 = 1.5 seconds

 

Then.....the max ht =    -16(1.5)^2 + 48(1.5) + 15  =  -16(2.25) + 72 + 15 =  51 ft

 

Here's the graph........https://www.desmos.com/calculator/poqqwhpqok

 

 

cool cool cool

CPhill Dec 17, 2015
 #3
avatar+8581 
+5

Thank you so so so much Mr.CPhill!!

I've been stuck on it for a long time!

 Dec 17, 2015

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