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The height in ft of a ball after t seconds is given by h=80t-16t^2. how long did it take for the ball to hit the ground

 Aug 28, 2017

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 #1
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The height in ft of a ball after t seconds is given by h=80t-16t^2. how long did it take for the ball to hit the ground

 

The height is equal to zero when the ball is on the ground.

 

\(\color{red} h=80t-16t^2=0\\ t(80-16t)=0 \)

\(t_1=0\)                   The ball is still lying on the ground.

\(80-16t=0\\ 16t=80\\ t=\frac{80}{16}\)

\(t_2=5\)                  The ball has landed.

laugh  !

 Aug 28, 2017
 #1
avatar+8079 
+1
Best Answer

The height in ft of a ball after t seconds is given by h=80t-16t^2. how long did it take for the ball to hit the ground

 

The height is equal to zero when the ball is on the ground.

 

\(\color{red} h=80t-16t^2=0\\ t(80-16t)=0 \)

\(t_1=0\)                   The ball is still lying on the ground.

\(80-16t=0\\ 16t=80\\ t=\frac{80}{16}\)

\(t_2=5\)                  The ball has landed.

laugh  !

asinus Aug 28, 2017

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