The height in ft of a ball after t seconds is given by h=80t-16t^2. how long did it take for the ball to hit the ground

Guest Aug 28, 2017

#1**+1 **

The height in ft of a ball after t seconds is given by h=80t-16t^2. how long did it take for the ball to hit the ground

**The height is equal to zero when the ball is on the ground.**

\(\color{red} h=80t-16t^2=0\\ t(80-16t)=0 \)

\(t_1=0\) The ball is still lying on the ground.

\(80-16t=0\\ 16t=80\\ t=\frac{80}{16}\)

\(t_2=5\) The ball has landed.

!

asinus
Aug 28, 2017

#1**+1 **

Best Answer

The height in ft of a ball after t seconds is given by h=80t-16t^2. how long did it take for the ball to hit the ground

**The height is equal to zero when the ball is on the ground.**

\(\color{red} h=80t-16t^2=0\\ t(80-16t)=0 \)

\(t_1=0\) The ball is still lying on the ground.

\(80-16t=0\\ 16t=80\\ t=\frac{80}{16}\)

\(t_2=5\) The ball has landed.

!

asinus
Aug 28, 2017