The image shows quadrilateral ABCD. Please answer with a response to each question below, thank you.
Here's my best shot
A. AB and CD must be the same length and have the same slope
B.
AB = sqrt [ 3 - 0)^2 + (4-0)^2 ] = sqrt ( 3^2 + 4^2) = sqrt (25) = 5
CD = sqrt [ (4 - 7)^2 + (7-3)^2 ] = sqrt [ (-3)^2 + 4^2] = sqrt (25) = 5
Slope of AB = [ 4-0] / [0 - 3] = -4/3
Slope of CD = [7 - 3 ] / [4 - 7] = -4/3
C. We only need to show that AD and BC = 5 (they are)
D. If we can prove that AD = BC =5 and AD is perpendicular to AB and BC is perpendicular to CD.....we will have a square [ these are true, as well ]