The interior angle measures of a pentagon form an arithmetic progression. The difference between the largest and smallest angle measures is 48 degrees. Find the measure of the smallest angle, in degrees.
Call the common difference between the angles, D
And call the measure of the smallest angle, A
And we know that the sum of the interior angles = (5-2) (180) = 3 *180 = 540°
So we have that
A + (A + D ) + (A + 2D) + (A + 3D) + (A + 4D) = 540
5A + 10D = 540 (1)
And we know that (A + 4D) - A = 48
So, simplifying.......4D = 48
D = 12 (2)
Sub (2) into (1) and we have that
5A + 10(12) = 540
5A + 120 = 540
5A = 540 -120
5A = 420
A = 420/5 = 84°