the length of a picture is 11.75 inches less than twice the width. if the perimeter of the picture is 102.5 inches, find its dimensions.
+118723 Let the width be w
the length is 2w-11.75 inches
Perimeter = 2l+2w
$$\\102.5=2(2w-11.75)+2w\\\\
102.5=2[(2w-11.75)+w]\\\\
51.25=2w-11.75+w\\\\
63=3w\\\\
w=21 \;\;inches\\\\
l=2*21-11.75\\\\
l=30.25\;\;inches\\\\
check\\\\
P=2(30.25+21)=102.5\;\;inches\\\\
$all looks good$$$
+118723 Let the width be w
the length is 2w-11.75 inches
Perimeter = 2l+2w
$$\\102.5=2(2w-11.75)+2w\\\\
102.5=2[(2w-11.75)+w]\\\\
51.25=2w-11.75+w\\\\
63=3w\\\\
w=21 \;\;inches\\\\
l=2*21-11.75\\\\
l=30.25\;\;inches\\\\
check\\\\
P=2(30.25+21)=102.5\;\;inches\\\\
$all looks good$$$
