The length of a rectangle is 6 yds longer than its width. If the perimeter of the rectangle is 48 yd, find its area.
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The length of a rectangle is 6 yds longer than its width. If the perimeter of the rectangle is 48 yd, find its area.
width = w
length = w + 6
perimeter = 2w + 2l = 2w + 2(w + 6)
48 = 4w + 12
4w = 36
w = 9
l = w + 6 = 9 + 6
l = 15
Area = length times width
A = 9 • 15
A = 135
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