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The length of a rectangle is 6yds longer than its width. If the perimeter of the rectangle is 72yds, find its length and width.

 Mar 22, 2019

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L = 6 + w    given

Perimeter = 2 * L + 2 * W

2 (6+w) + 2w = 72

12 + 2w + 2w = 72

4w = 60

w=15        L = 6+w = 21

 Mar 22, 2019
 #1
avatar+21931 
0
Best Answer

L = 6 + w    given

Perimeter = 2 * L + 2 * W

2 (6+w) + 2w = 72

12 + 2w + 2w = 72

4w = 60

w=15        L = 6+w = 21

ElectricPavlov Mar 22, 2019

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