The line with equation x + y = 0 coincides with the terminal side of an angle θ in standard position in Quadrant  II.

What is the value of tanθ?

Guest Dec 8, 2017

x + y  =  0


y  =  -1x


Any point on this line in quadrant II will have the coordinates  (-a, a)....and this will be the terminal point on θ


So   tan θ =   a / -a  =   -1



cool cool cool

CPhill  Dec 8, 2017

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