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The mass of the earth is 5.98x10^24 kg and its radius is 6.38x10^6 m. Compute the density of the earth, using the power of 10 notations and the correct number of significant figures.

 Aug 27, 2015

Best Answer 

 #1
avatar+118696 
+5

The mass of the earth is 5.98x10^24 kg and its radius is 6.38x10^6 m. Compute the density of the earth, using the power of 10 notations and the correct number of significant figures.

 

V=43πr3V=43π(6.38106)3V=43π6.3831018Density=MassVolumeDensity=5.98102443π6.3831018Kg/m3Density=35.981064π6.383Kg/m3

 

(3×5.98)(4×π×6.383)=0.0054973139299626

 

Density=35.981064π6.383Kg/m3Density=0.0054973139299626106Kg/m3Density=5.4973139299626103Kg/m3

 

Now volume and mass both have 3 significant figures so I think density has 3 significant figures too.

 

Density=5.50103Kg/m3

 

Here are some clips to help you understand

 

https://www.youtube.com/watch?v=VRtR-rv96rg

https://www.youtube.com/watch?v=__csP0NtlGI

 Aug 27, 2015
 #1
avatar+118696 
+5
Best Answer

The mass of the earth is 5.98x10^24 kg and its radius is 6.38x10^6 m. Compute the density of the earth, using the power of 10 notations and the correct number of significant figures.

 

V=43πr3V=43π(6.38106)3V=43π6.3831018Density=MassVolumeDensity=5.98102443π6.3831018Kg/m3Density=35.981064π6.383Kg/m3

 

(3×5.98)(4×π×6.383)=0.0054973139299626

 

Density=35.981064π6.383Kg/m3Density=0.0054973139299626106Kg/m3Density=5.4973139299626103Kg/m3

 

Now volume and mass both have 3 significant figures so I think density has 3 significant figures too.

 

Density=5.50103Kg/m3

 

Here are some clips to help you understand

 

https://www.youtube.com/watch?v=VRtR-rv96rg

https://www.youtube.com/watch?v=__csP0NtlGI

Melody Aug 27, 2015

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