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The midpoint of the line segment between $(x,y)$ and $(-9,1)$ is $(3,-5)$. Find $(x,y)$.

Guest Nov 22, 2017

Best Answer 

 #1
avatar+1493 
+2

Use the midpoint formula to get you started and then work from there!
 

The midpoint formula tells you to find the average of the x-coordinates and y-coordinates. 

 

\((\frac{x-9}{2},\frac{y+1}{2})\)Now that we have the expression for both the x- and y-coordinate, solve for the individual variables. 
\(\frac{x-9}{2}=3\)\(\frac{y+1}{2}=-5\)

 

Multiply both equations by 2 to eliminate the fraction.
\(x-9=6\)\(y+1=-10\)

 

Subtract the constant to isolate the variable.
\(x=15\)\(y=-11\)

 

 
\((15,-11)\)This is the coordinate.
  
TheXSquaredFactor  Nov 22, 2017
edited by TheXSquaredFactor  Nov 22, 2017
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1+0 Answers

 #1
avatar+1493 
+2
Best Answer

Use the midpoint formula to get you started and then work from there!
 

The midpoint formula tells you to find the average of the x-coordinates and y-coordinates. 

 

\((\frac{x-9}{2},\frac{y+1}{2})\)Now that we have the expression for both the x- and y-coordinate, solve for the individual variables. 
\(\frac{x-9}{2}=3\)\(\frac{y+1}{2}=-5\)

 

Multiply both equations by 2 to eliminate the fraction.
\(x-9=6\)\(y+1=-10\)

 

Subtract the constant to isolate the variable.
\(x=15\)\(y=-11\)

 

 
\((15,-11)\)This is the coordinate.
  
TheXSquaredFactor  Nov 22, 2017
edited by TheXSquaredFactor  Nov 22, 2017

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