The minimal value of F(x)=x^2-2x+p is -2.Find the constant value of p.
F(x)=x^2-2x+p
F '(x) = 2x - 2
Set to 0, and this function has a minimum when x = 1
So
F(1) = -2
(1)^2 - 2(1) + p = -2
1 - 2 + p = -2
-1 + p = -2 add 1 to both sides
p = -1
+4 
