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A particle is moving with the given data. Find the position of the particle.

a(t) = 2t + 3,    s(0) = 6,    v(0) = −9

 Oct 5, 2019
 #1
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\(\text{We start with the acceleration to find the velocity}\\ v(t) = \displaystyle \int_0^t a(\tau) d\tau + v_0 = t^2+3t-9\\~\\ s(t) = \displaystyle \int_0^t v(\tau)d\tau + s_0 = \dfrac{t^3}{3}+\dfrac 3 2 t^2 - 9t + 6\)

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 Oct 5, 2019
 #2
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thanks a lot :)

Guest Oct 5, 2019

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