The ninth and tenth terms of an arithmetic sequence are \(\frac14\) and \(\frac13\), respectively. What is the second term?
If you understand the answer to solving the problem given the 16th and 17th terms, work this problem in a similar fashion.
1/4 is equivalent to 3/12
1/3 is equivalent to 4/12
So if we conclude that this arithmetic sequence is the addition of 1/12 to each term, then:
–5/12 –4/12 –3/12 –2/12 –1/12 0/12 1/12 2/12 3/12 4/12
1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th
second term –4/12 = –1/3