+45 x(t) = 12 cos (5t) + 4 sin (5t)
What is the acceleration of the block after 3 seconds?
+37146 Take the derivative twice then substitute t=3 into the equation
x' = -12sin(5t) + 4cos(5t)
x" = -12cos(5t) - 4sin(5t)
= -12cos(15) -4sin(15)
= -12.62 units/time^2 I think.
You might think, but you're wrong.
The derivative of sin (5t), (for example) is 5cos (5t), not simply cos (5t).
+37146 Take the derivative twice then substitute t=3 into the equation
x' = -12sin(5t) + 4cos(5t)
x" = -12cos(5t) - 4sin(5t)
= -12cos(15) -4sin(15)
= -12.62 units/time^2 I think.
Guest is right....Thanx for the correction !
x' = - 60 sin (5t) + 20 cos(5t)
x" = - 300 cos (5t) - 100sin (5t)
when t = 3 then x" = -315.66
