\(\dfrac{2}{3}x-8=0\\ \dfrac{2}{3}x=8\\ x = 8\times \dfrac{3}{2} = 12\)
OR
If you mean 2/3x - 8 = 0 instead of 2/3 x - 8 = 0...... ('A dot can make extreme difference.' a Chinese idiom translated by me.)
\(\dfrac{2}{3x}-8=0\\ \dfrac{2}{3x}=8\\ \dfrac{1}{x}=8\times \dfrac{3}{2} \\ \dfrac{1}{x}=12\\ x=\dfrac{1}{12}\text{ OR }0.08\bar{3}\text{ <-- the bar is for repeating notation.}\)