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The quadratic 3x^2-24x+72 can be written in the form a(x+b)^2+c where a, b, and c, are constants.  What is a+b+c?

 

 

thanks so much for the help!

 Oct 20, 2017
 #1
avatar+98125 
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 3x^2 - 24x + 72      factor out  the 3

 

3 [ x^2  -  8x  +  24 ]

 

Take 1/2 of 8  = 4........square it =  16....add and subtract it

 

3 [ x^2 - 8x + 16 +  24 - 16 ]

 

Factor the first three terms and simplify

 

3 [ ( x - 4)^2 + 8 ]

 

3 (x - 4)^2  + 24

 

a + b + c  =

 

3 + (-4) + 24  =

 

-1 + 24

 

23

 

 

cool cool cool

 Oct 20, 2017

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