The radius of a circle is 6 centimeters. What is the area of a sector bounded by a 45° arc?
+1694 The radius of a circle is 6 cm. What is the area of a sector bounded by a 45° arc?
$${\mathtt{A}} = {\frac{{{\mathtt{r}}}^{{\mathtt{2}}}{\mathtt{\,\times\,}}{\mathtt{\pi}}}{{\mathtt{8}}}}$$
$${\mathtt{A}} = {\frac{{{\mathtt{6}}}^{{\mathtt{2}}}{\mathtt{\,\times\,}}{\mathtt{3.141\: \!59}}}{{\mathtt{8}}}}$$
$${\mathtt{A}} = {\mathtt{14.137}}$$cm2
+129852 The area is given by....
A = (1/2) r^2 (Θ ) where A is the area and Θ is the radian measure if the arc....so we have
A = (1/2) 6^2 * (pi / 4) = 36 pi / 8 = about 14.14 cm^2
+1694 The radius of a circle is 6 cm. What is the area of a sector bounded by a 45° arc?
$${\mathtt{A}} = {\frac{{{\mathtt{r}}}^{{\mathtt{2}}}{\mathtt{\,\times\,}}{\mathtt{\pi}}}{{\mathtt{8}}}}$$
$${\mathtt{A}} = {\frac{{{\mathtt{6}}}^{{\mathtt{2}}}{\mathtt{\,\times\,}}{\mathtt{3.141\: \!59}}}{{\mathtt{8}}}}$$
$${\mathtt{A}} = {\mathtt{14.137}}$$cm2
