The reaction of 32.7 mL of N2 gas with 173 mL of H2 gas to form ammonia (NH3) via the equation:
N2 (g) + 3 H2 (g) → 2 NH3 (g)
will produce __________ mL of ammonia if pressure and temperature are kept constant.
There is 22.4 l of gas in a mole of the gas (at STP).....no matter what the gas is..
we can treat these volumes of gas as 'mole equivalents'
32.7 moles of N2 require 3 x 32.7 =98.1 moles of H2 for no reactants to be leftover....
there is more than enough H2 to have some left over....but all of the 32.7 moles of N2 will be used
the ratio of N2 to NH3 produced is 1 to 2
so there will be twice as much NH3 produced as the starting amount of N2
65.4 ml of NH3 (ammonia) produced