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The right pyramid shown has a square base and all eight of its edges are the same length. What is the degree measure of angle $ABD$?

AdminMod2  Sep 17, 2017

Best Answer 

 #1
avatar+26971 
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Let all sides have length 1

 

Distance BD = sqrt(2)

 

Half of BD = sqrt(2)/2

 

cos(ABD) = (sqrt(2)/2)/1 

 

ABD = cos-1(sqrt(2)/2) → 45 degrees

Alan  Sep 17, 2017
 #1
avatar+26971 
+1
Best Answer

Let all sides have length 1

 

Distance BD = sqrt(2)

 

Half of BD = sqrt(2)/2

 

cos(ABD) = (sqrt(2)/2)/1 

 

ABD = cos-1(sqrt(2)/2) → 45 degrees

Alan  Sep 17, 2017

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