The spherical coordinates of \((-3, 4, -12)\) are \((\rho, \theta, \phi)\). Find \(\tan \theta + \tan \phi\).
(-3, 4, -12)
tan θ= y/x = 4/-3
tan Φ = √ [ x^2 + y^2 ] / z = 5 / -12
And their sum is
-4/3 + - 5/12 =
-16/12 - 5/ 12 =
-21 / 12 =
-7 / 4
+489 
