The spherical coordinates of $(-3, 4, -12)$ are $(\rho, \theta, \phi)$ . Find $\tan \theta + \tan \phi$ .

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The spherical coordinates of $(-3, 4, -12)$ are $(\rho, \theta, \phi)$ . Find $\tan \theta + \tan \phi$ .

RektTheNoob Dec 4, 2018

CPhill · Answer 1 · 2018-12-04T05:50:58

(-3, 4, -12)

tan θ= y/x = 4/-3

tan Φ = √ [ x^2 + y^2 ] / z = 5 / -12

And their sum is

-4/3 + - 5/12 =

-16/12 - 5/ 12 =

-21 / 12 =

-7 / 4

The spherical coordinates of (−3,4,−12)(-3, 4, -12) are (ρ,θ,ϕ)(\rho, \theta, \phi). Find tanθ+tanϕ\tan \theta + \tan \phi.