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The spherical coordinates of \((-3, 4, -12)\) are \((\rho, \theta, \phi)\). Find \(\tan \theta + \tan \phi\).

 Dec 4, 2018
 #1
avatar+100519 
+2

(-3, 4, -12)

 

tan θ= y/x = 4/-3

tan Φ = √ [ x^2 + y^2 ] / z = 5 / -12

 

And their sum is 

 

  -4/3 + - 5/12  =  

 

-16/12 - 5/ 12 =

 

-21 / 12 =

 

-7 / 4

 

 

cool cool cool

 Dec 4, 2018

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