The sum of 4 consecutive integers is 326.

x=1st integer   then x+1  x+2 and x+3   all add up to 326

x +  x+1  + x+2  +  x+3 = 326

4x +6 = 326

4x= 320

x = 80

 

the Second number is 81

x + x + 1 + x + 2 + x + 3=326

4x=326 - 6=320

x=320/4=80

80 + 81 + 82 + 83 =326