The terminal ray of ∠A passes through the point (10,−4) . ∠A is drawn in standard position. What is the value of secA ?

Guest Feb 6, 2020

#1**+1 **

sec = 1/cos

10, -4 use pythagorean theorem to find the hypotenuse 10^2 +(-4)^2 = h^2 h = sqrt 116

cos = adj/hyp = 10 / sqrt 116

sec = 1/cos = sqrt 116/10 = 2sqrt29/10 = sqrt 29 / 5

ElectricPavlov Feb 6, 2020