The terminal ray of ∠A passes through the point (10,−4) . ∠A is drawn in standard position. What is the value of secA ?
+36916 sec = 1/cos
10, -4 use pythagorean theorem to find the hypotenuse 10^2 +(-4)^2 = h^2 h = sqrt 116
cos = adj/hyp = 10 / sqrt 116
sec = 1/cos = sqrt 116/10 = 2sqrt29/10 = sqrt 29 / 5
