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The terminal ray of ∠A passes through the point (10,−4) . ∠A  is drawn in standard position.

What is the value of secA ?

 Mar 10, 2020
 #2
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First find the hypotenuse

 

sqrt (10^2 +(-4)^2 = 10.77

 

cos = adj/hypotenuse

       = 10/10.77 = .92847          sec = 1/cos = 1/.92847 = 1.077

 Mar 10, 2020

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