+0  
 
0
46
1
avatar

The terminal ray of  ∠A passes through the point (−6,3) .

∠A  is drawn in standard position.

What is the value of secA ?

Enter your answer as an exact answer, in simplified form, in the box.

 May 1, 2020
 #1
avatar+111329 
+1

sec A  =  r  / x

 

r =  sqrt  [ (-6)^2  + 3^2 ]  = sqrt  [ 36 + 9 ] =  sqrt [45 ]  = 3sqrt (5)

 

So

 

sec A  =   3sqrt (5) / -6    =    - sqrt (5) / 2

 

 

cool cool cool

 May 1, 2020

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