The terminal ray of angle θ drawn in standard position passes through (−1,3). What is the value of cscθ?Enter answer in simplest form

Find the hypotenuse length     sqrt ((-1)^2 + 3^2) =   sqrt 10  

          sin of the angle is  3/sqrt10       csc is 1/sin   =   sqrt10/3    or  1/3  sqrt10