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The terminal ray of angle β, drawn in standard position, passes through the point (−7, 23√).

What is the value of cosβ?

Enter your answer, in simplest radical form, in the box.

 Mar 12, 2021

Best Answer 

 #1
avatar+31281 
+2

 

Is that point given   (-7,\(\sqrt{23}\) )     ??    I will assume it is

 

Find hypoytenuse length of the terminal ray  ( or magnitude)

  = sqrt (  (-7)^2  + (sqrt23)^2 )     = sqrt  (49 + 23) = sqrt 72

 

 

cos   = -7 / sqrt (72)    = - 7/ (6sqrt 2)     

 Mar 12, 2021
 #1
avatar+31281 
+2
Best Answer

 

Is that point given   (-7,\(\sqrt{23}\) )     ??    I will assume it is

 

Find hypoytenuse length of the terminal ray  ( or magnitude)

  = sqrt (  (-7)^2  + (sqrt23)^2 )     = sqrt  (49 + 23) = sqrt 72

 

 

cos   = -7 / sqrt (72)    = - 7/ (6sqrt 2)     

ElectricPavlov Mar 12, 2021

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