+0  
 
0
452
3
avatar

The terminal side of θ passes through the point  (−3,7).

What is the exact value of sinθ in simplified form?

758√58

−758√58

358√58

−358√58

 

Enter the value of arccos (0.21) as a decimal to the nearest hundredth of a degree in the box.

 

What is the exact value of arccos (12)  in radians?

Guest Jan 13, 2018
 #1
avatar+87293 
+2

(-3, 7)  =  (x, y)

 

sin θ  =  y / r    =  7 / r

 

Where  r  = √  [x^2 + y^2  ]  =  √ [ (-3)^2 + 7^2]  =  √58

 

So

 

sin  θ  =  7 / √ 58

 

 

arccos (0.21)  ≈  77.88°

 

 

arccos (12)  is impossible.....since    -1 ≤ cosθ ≤  1

 

 

cool cool cool

CPhill  Jan 13, 2018
 #2
avatar
+1

I apologize, its not 12, its (1/2)

Guest Jan 13, 2018
 #3
avatar+7153 
+1

arccos( 1/2 )   =   60°   =   π/3   radians

hectictar  Jan 13, 2018

17 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.