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The terminal side of θ passes through the point  (−3,7).

What is the exact value of sinθ in simplified form?

758√58

−758√58

358√58

−358√58

 

Enter the value of arccos (0.21) as a decimal to the nearest hundredth of a degree in the box.

 

What is the exact value of arccos (12)  in radians?

 Jan 13, 2018
 #1
avatar+101084 
+2

(-3, 7)  =  (x, y)

 

sin θ  =  y / r    =  7 / r

 

Where  r  = √  [x^2 + y^2  ]  =  √ [ (-3)^2 + 7^2]  =  √58

 

So

 

sin  θ  =  7 / √ 58

 

 

arccos (0.21)  ≈  77.88°

 

 

arccos (12)  is impossible.....since    -1 ≤ cosθ ≤  1

 

 

cool cool cool

 Jan 13, 2018
 #2
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+1

I apologize, its not 12, its (1/2)

 Jan 13, 2018
 #3
avatar+8071 
+1

arccos( 1/2 )   =   60°   =   π/3   radians

 Jan 13, 2018

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