The three-digit numbers C99, A6A, BC7, and B91 form an arithmetic sequence in this order. What is the value of A2 + B2 + C2 ?
I need a step by step or an explanation of how to do this problem, please. I don't understand how to solve this. Someone help.
We can say
First equation means d = A6A-C99
Second gives us d=BC7-A6A
From this we see that the ones digit on the right side must be 6 (9+7)
So digit A must be 8 or 3.
From the third equation we can see that d must have a ones digit of 4
Therefore A must be 3.
Knowing this, C99+d=363
We can guess that C is one or two by saying d is positive(Big assumption-_-)
if c is two then d=64
B must be four then if the assumption is correct
WE ARE CORRECT!!!!!!
Hope this helps