The values of a1, n, and r are given for the following geometric sequences. Find the sum of the terms of each sequence:
a1 = –2, n = 4, r=–3
The sum of the tems of the series are given by
Sn = a1 [ 1 + r^n ] / [1 - r ]
So....the sum of the first 4 terms =
-2 [ 1 - (-3)^4] / [ 1 - (-3) ] =
-2 [ -80] / [4] =
160 / 4 =
40
Sum=40