The vector 12π’ + ππ£ is parallel to the vector 9π’ β π£. Find the value of the constant π
\(\text{in two dimensions the ratio of the x and y coordinates}\\ \text{of parallel vectors will be equal}\\ \dfrac{q}{12} = \dfrac{-1}{9}\\ 9q = -12\\ q = -\dfrac 4 3 \)
