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The vector 12𝐒 + π‘žπ£ is parallel to the vector 9𝐒 βˆ’ 𝐣. Find the value of the constant π‘ž

 Feb 23, 2019
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\(\text{in two dimensions the ratio of the x and y coordinates}\\ \text{of parallel vectors will be equal}\\ \dfrac{q}{12} = \dfrac{-1}{9}\\ 9q = -12\\ q = -\dfrac 4 3 \)

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 Feb 23, 2019

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