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There are 5 girls and 5 boys in a chess club. The club holds a round-robin tournament in which every player plays against every other player exactly once.  In how many games does a girl play against a different girl?

 Oct 23, 2020
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5 girls must play against 4 other girls = 20 games  BUT 2 girls play in each game so divide by 2  =   10 games

 

 

 

or another way:

5 c 2 = 10 games

 Oct 23, 2020

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