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 There are four red b***s and two white b***s in a jar. One ball is randomly removed and replaced with a ball of the opposite color. The jar

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There are four red b***s and two white b***s in a jar. One ball is randomly removed and replaced with a ball of the opposite color. The jar is then shaken and one ball is randomly selected. What is the probability that this ball is red? Express your answer as a common fraction.

 Apr 15, 2015

Best Answer 

 #1
avatar+118723 
+10

I think....

4 red and 2 white

P(white removed and then red is chosen) = 2/6 * 5/6 = 10/36 = 5/18

P(red removed and then red is chosen) = 4/6 * 1/2 = 4/12 = 1/3 = 6/18

P(red is chosen) = 5/18 +6/18 = 11/18

 Apr 15, 2015

1+0 Answers

 #1
avatar+118723 
+10
Best Answer

I think....

4 red and 2 white

P(white removed and then red is chosen) = 2/6 * 5/6 = 10/36 = 5/18

P(red removed and then red is chosen) = 4/6 * 1/2 = 4/12 = 1/3 = 6/18

P(red is chosen) = 5/18 +6/18 = 11/18

Melody Apr 15, 2015

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