There are values A and B such that (x + B) / (x^2-7x+10) = A/(x-2) + 3/(x-5).
Find A+B
+36916 Put right side over common denominator
(Ax-5A + 3x-6 ) / (x^2-7x+10) now equate the L and R numerators
Ax + 3x - 5A -6 = x + B and equate the components
Ax + 3x = x
A = -4
then:
-5A-6 = B
-5(-4) - 6 =B
14 = B
