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There exists a real number k such that the equation \(\[\begin{pmatrix} -1 \\ -2 \end{pmatrix} + t \begin{pmatrix} \phantom -3 \\ -2 \end{pmatrix} = \begin{pmatrix} 5 \\ 0 \end{pmatrix} + s \begin{pmatrix} 4 \\ k \end{pmatrix}\]\)
does not have any solutions in t and s. find K

 Feb 8, 2022
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k = 7/3.

 Jul 11, 2022

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