Triangle ABC is an isosceles triangle with side lengths of 25, 25 and 48 centimeters. What is the area of triangle ABC, in square centimeters?

Guest Nov 14, 2017

#1**+1 **

25 units = a line segment starting at (-24, 0) and ending at (0, n)

Pythagorean theorem: \(625 = 576 - n^2\)

625 - 576 = 49

\(\sqrt{49} = 7\)

n = 7

Now that we have the height and the width, we solve using \(a = \frac{1}{2}bh\)

\(7 \times 48 \div 2=7\times 24 = 168\)

The area of the triangle is 168 square centimeters.

^^^ I honestly don't know how I managed to use that method. ^^^

helperid1839321
Nov 14, 2017