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theta is Q4 angle, such that Sin(theta)=-5/8 . So, what is Sec(theta) and tan(theta) in exact values?

Here is exact question:

 

 Mar 8, 2019

Best Answer 

 #1
avatar+102372 
+1

We need to find x

 

sqrt (8^2 -5^2)  = sqrt (64 - 25 )  =   sqrt (39)  = x

 

sec (theta)  = r / x  =  8/ sqrt (39)  =  8sqrt (39) / 39

 

tan (theta)  =  y / x  =  -5/ sqrt (39) =  -5sqrt (39) / 39

 

cool cool cool

 Mar 8, 2019
 #1
avatar+102372 
+1
Best Answer

We need to find x

 

sqrt (8^2 -5^2)  = sqrt (64 - 25 )  =   sqrt (39)  = x

 

sec (theta)  = r / x  =  8/ sqrt (39)  =  8sqrt (39) / 39

 

tan (theta)  =  y / x  =  -5/ sqrt (39) =  -5sqrt (39) / 39

 

cool cool cool

CPhill Mar 8, 2019
 #2
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+1

Thank you!!smiley

Guest Mar 8, 2019

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