THIS IS HARD

$sin2\theta=cos\theta$

Apply the double angle identity to sin2θ.

$2sin\theta cos\theta=cos\theta$

$2sin\theta cos\theta-cos\theta=0$

$(cos\theta)(2sin\theta-1)=0$

$cos\theta=0$

$\theta=90°,270°$

$2sin\theta-1=0$

$\frac{1}{2}=sin\theta$

$\theta=30°,150°$

Therefore, θ can be equal to 30°, 90°, 150°, 270°