Rhombus ABCD has perimeter 148, and one of its diagonals has length 24. How long is the other diagonal?
All ides are equal....so......one side is
148/ 4 = 37 units
And the diagonals bisect each other and meet at right angles
And the side forms the hypotenuse of a right triangle and another leg is 1/2 of a diagonal length.....and the remaining leg is 1/2 of the other diagonal length
So....the length of the other diagonal is
2 * √ [ 37^2 - 12^2 ] = 2 √1225 = 2 * 35 = 70 units