This is the last question pls help thanks

A and B departed from a town together for another town 45 km away. If the speed of A is 1 km/h more than that of B, he reaches his destination half an hour earlier than B. Find the speed of A and B.

Here is another way:
S = Speed of B
S+1 =Speed of A
T = Time of arrival.
45/S = T........................(1)
45/(S+1) =T - 1/2.........(2), solve for S, T
S =9 km/h - speed of B
T = 5 hours - time of B
9+1 =10 km/h - speed of A
5 - 1/2 =4 1/2 hours - time of A