+0  
 
0
233
3
avatar

GRRR I HATE THIS!!! 

 

Can someone put me onto the right track for this one, dont tell me the answer, just tell me how to solve it please.

 

Graph- https://imgur.com/a/kKaSq

 

Question- Round all real zeros in the graph to the nearest integer and find a polynomial function P of lowest degree, with the absolute value of the leading coefficient equal to 1, that has the indicated graph. 

 

K thx

Guest Jun 1, 2017
 #1
avatar
+1

NVM

 

I got it

 

x = -3 is a zero of multiplicity 2, x = 0 is a zero of multiplicity 1 and x = 2 is a zero of multiplicity 2.

 

P(x) = -x(x + 3)2(x - 2)2 : polynomial with real zeros hence with lowest degree.

Guest Jun 1, 2017
 #2
avatar+92751 
+1

Yes that is correct :)

Melody  Jun 1, 2017
 #3
avatar+92751 
0

Of course  this will not give the correct max and mins. It just gives the correct basic shape and the correct zeros.

Melody  Jun 1, 2017

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