GRRR I HATE THIS!!!
Can someone put me onto the right track for this one, dont tell me the answer, just tell me how to solve it please.
Question- Round all real zeros in the graph to the nearest integer and find a polynomial function P of lowest degree, with the absolute value of the leading coefficient equal to 1, that has the indicated graph.
I got it
x = -3 is a zero of multiplicity 2, x = 0 is a zero of multiplicity 1 and x = 2 is a zero of multiplicity 2.
P(x) = -x(x + 3)2(x - 2)2 : polynomial with real zeros hence with lowest degree.