Three consecutive positive odd integers a, b and c satisfy b^2 - a^2 = 348 and c^2 - b^2 > 0. What is the value of c^2 - b^2?
a = a
b = a + 2
c = a + 4
b^2 - a^2 = 348
(b+a)(b-a) = 348
(a+2+a)(a+2-a) = 348
Solve for a and you'll have b and c. :))
=^._.^=
